A U-tube containing a liquid is accelerated horizontally with a constant acceleration `a_0`. If the separation between the vertical limbs is l find the difference in the heights of the liquid in the two arms.

Options

A. Zero
B. `l`
C. `(la_0)/(g)`
D. `(lg)/(a_0)`

Answer

C

Explanation

(c ) We know , `tan theta = (a)/(g)`
in the present problem, `tan theta =(h)/(l)`
So `(h)/(l) = (a)/(g) or h = (al)/(g)`
(where h is the difference in the heights in the two limbs)