A glass beaker of mass 400 kg floats in water with the open end just touching the surface of water and half of the beaker filled with water. The inner volume of the beaker is `500 cm^3` What is the density of the meterial of the beaker ?

Options

A. `1.52 g cm^(-3)`
B. `2.67 g cm^(-3)`
C. `3.01 g cm^(-3)`
D. `3.87 g cm^(-3)`

Answer

B

Explanation

(b) Mass of water in the beaker = 250 xx1 = 250 g Mass of beaker + Mass of water in it = mass of the volume fo water displaced = 400 + 250 = 650g So volume of water displaced ` =650 cm^3` As the inner volume ` =500 cm^3` So volume of the meterial of beaker ` =650 - 500 = 150 cm^3`
`:. Density = (400)/(150) = 2.67 g//cm^3`