Tow bodies are in equilibrium when suspended in water from the arms of balance. The mass of one body is 36 g and its density is `9 g// cm^3` If the mass of the other is 46 g, its density in `g//cm^3` is

Options

A. `(4)/(3)`
B. `(3)/(2)`
C. 3
D. 5

Answer

C

Explanation

(c ) Apperent weight ` = V (rho - sigma) = (m_2)/(rho_2) (rho_2 - sigma)`
`rArr (36)/(9) (9-1) = (48)/(rho_2) (rho_2 -1)`
By solving we get `rho_2 = 3.`