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In figure, block A hangs by a cord form ...

In figure, block `A` hangs by a cord form spring balance `D` and it submerged in a liquid `C` contained in a beaker `B`. The mass of the beaker is `1 kg`. The mass of the liquid is `1.5 kg`. Balance `D` reads `7.5 kg`. The volume of block `A` is `0.003 m^(3)`. The mass per unit volume of the liquid is

A

`2500 kg m^(-3)`

B

`5000 kg m^(-3)`

C

`1 kg m^(-3)`

D

`(5000)/(3) kg m^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`7.5g = 1 g +1.5g+Downward reaction of block or `5g = | Downward reaction force|`
`=|upthrust|=0.003 rho_(1)g`
`:. Rho_(1) = 5/0.003 kgm^(-3) = 5000/3 kg m^(-3)`.
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Knowledge Check

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