In figure, block `A` hangs by a cord form spring balance `D` and it submerged in a liquid `C` contained in a beaker `B`. The mass of the beaker is `1 kg`. The mass of the liquid is `1.5 kg`. Balance `D` reads `7.5 kg`. The volume of block `A` is `0.003 m^(3)`. The mass per unit volume of the liquid is

Options

A. `2500 kg m^(-3)`
B. `5000 kg m^(-3)`
C. `1 kg m^(-3)`
D. `(5000)/(3) kg m^(-3)`

Answer

D

Explanation

`7.5g = 1 g +1.5g+Downward reaction of block or `5g = | Downward reaction force|`
`=|upthrust|=0.003 rho_(1)g`
`:. Rho_(1) = 5/0.003 kgm^(-3) = 5000/3 kg m^(-3)`.