Two solid pieces, one of gold and the other of silver when immersed completely in water have equal weights. When weighted in air:

Options

A. the gold piece will weigh more
B. the silver piece will weigh more
C. both will have the same weight
D. both will weigh less than they weigh in water

Answer

B

Explanation

Suppose weight of gold in air = x g
weight of silver in air = `y g`
Density of gold = `d_(1)`
Density of silver = d_(2) (where d_(1) gt d_(2)`)
Volume of gold = (x)/(d_1), volume of silver = `(y)/(d_2)`
As weight of gold in water = weigth of silver in water
`(x-(x)/(d_1)xx1) g = (y-(x)/(d_2)xx1)g`
`=x/y = ((1-(1)/(d_2)))/((1-(1)/(d_1))) lt 1 or x lt y or y gt x`
i.e., weight of silver in air is more than that of gold in air.