A block of ice of area `A` and thickness `0.5m` is floating in the fresh water. In order to just support a man of `100kg`. Find the area `A`. (the specific gravity of ice is `0.917` and density of water = 1000 kg//m^(3)`)

Options

A. `2.41 m^(2)`
B. `1.40 m^(2)`
C. `0.75 m^(2)`
D. None

Answer

A

Explanation

For equilibrium `(m_(1)+m_(2))g = rho V g`
Here, `m_(1) = mass of man = 100kg`
`m_(2) = mass of ice`
`0.917 xx 1000V = 917V`
`rho= 1000kg//m^(3)`
`h = 0.5m`

`:. 100g+917Vg = rho Vg = 1000 Vg`
`:. V = (100g)/(1000g-917g)`
`:. Ah = (100)/(83):. A = (100)/(83xx0.5) = 2.41m^(2)`.