An ideal gas has a volume of `3 V` at `2` atmosphere pressure. Keeping the temperature constant. Its pressure is doubled. The volume of the gas will be

Options

A. `6 V`
B. `3 V`
C. `1.5 V`
D. `1 V`

Answer

C

Explanation

Given:
Initial volume `V_(1) = 3V`
Initial pressure `P_(1) = 2` atmosphere
Final pressure
`P_(2) = 2P_(1) = 2 xx 2 = 4` atmosphere
According to the Boyle's law we have
`P_(1)V_(1) = P_(2)V_(2)` (where `V_(2)` is the final volume of gas)
`or 2 xx 3V = 4xxV_(2)` or `V_(2) = 1.5V`.