A constant pressure `V_(1)` and `V_(2)` are the volumes of a given mass of a gas at temperature `27^(@)C` and `54^(@)C` respectively. Then the ratio `(V_(1))/(V_(2))` will be

Options

A. `100/109`
B. `(sqrt(100/109))`
C. `10/54`
D. `54/10`

Answer

A

Explanation

Initial volume of gas = `V_(1)`
final volume of gas = `V_(2)`
initial temperature of gas `T_(1) = 27^(@)C = 300K`
Final temperature of gas `T_(2) = 54^(@)C = 327K`
Now from the Charles's law at constant pressure
`(V_(1))/(V_2) = (T_1)/(T_2) = (300)/(327) = 100/109`.