One mole of an ideal gas at temperature `T_` expands slowly according to the law `p/V=` constant.
Its final temperature is `T_2`. The work done by the gas is

Options

A. `R(T_(2) - T_(1))`
B. `2R(T_(2) - T_(1))`
C. `R/2(T_(2) - T_(1))`
D. `2R/3(T_(2) - T_(1))`

Answer

C

Explanation

`PV^(-1)=C`
Comparing `PV^(N) = C`
`N+-1`
`W=(nR(T_1-T_2))/(N-1) = (1xxR(T_1-T_2))/(-2)`
`W = (R(T_2-T_1))/(2)` .