One mole of an ideal gas at temperature `T_` expands slowly according to the law `p/V=` constant.
Its final temperature is `T_2`. The work done by the gas is

Options

A. `R(T_(2) - T_(1))`
B. `(R//2)(T_(2) - T_(1))`
C. `(R//4)(T_(2) - T_(1))`
D. `PV(T_(2) - T_(1))`

Answer

B

Explanation

`W = int_(V_1)^(V_2) PdV = int_(V_1)^(V_2) KV dV`
` (:' p/V = K = consta nt)`
`:. W = 1/2k(v_(2)^(2)-V_(1)^(2))` lt