At `10^(@)C`, the value of the density of a fixed mass of an ideal gas divided by its pressure is x. at `110^(@)C`, this ratio is

Options

A. `x`
B. `(383)/(283) x`
C. `(10)/(110) x`
D. `(283)/(383) x`

Answer

D

Explanation

Writing ideal 1 gas law, `PV = nRT`
`or `PV = m/M RT or `(PV)/(m) = 1/mRT`
or `p/(rho) = (RT)/(M) or (rho)/(P)= 1/T`
`:. (rho_(1)//P_(1))/(rho_(2)//P_(2)) = (T_2)/(T_1)`
`implies (x)/((rho_(2)//P_(2))) = (383)/(283) or (rho_2)/(P_2) = (283)/(383)x`.