The coefficient of performance of a refrigerator is 5. If the temperature inside freezer is `-20^(@)C`, the temperature of the surroundings to which it rejects heat is :

Options

A. `21^(@)C`
B. `31^(@)C`
C. `41^(@)C`
D. `11^(@)C`

Answer

B

Explanation

Coefficient of performance of refregetor
`COP = (T_L)/(T_(H)-T_(L))`
Where `T_(L) rarr` lower temperature
and `T_(H) rarr` higher temperature
so, `5=(T_L)/((T_(H)-T_(L))`
`implies T_(H) = 6/5T_(L)=6/5(253)=303.6K`.