A refrigerator works between `4^(@)C` and `30^(@)C`. It is required to remove `600 calories` of heat every second in order to keep the temperature of the refrigerator space constant.The power required is (Take `1calorie= 4.2 J`)

Options

A. `2.365W`
B. `23.65W`
C. `236.5W`
D. `2365W`

Answer

C

Explanation

`beta=(Q_(2))/(W) = (T_2)/(T_(1)-T_(2))`
Where `Q_(2)` is heat removed)
`implies (600xx4.2)/(W) = (277)/(303-277)`
`implies W = 236.5joule`