A satellite is orbiting around the earth in a circular orbit and in this orbit magnitude of its acceleration is `a_1` . Now a rocket is fired in the direction of motion of satellite from the satellite due to which its speed instantaneously becomes half of initial, just after the rocket is fired acceleration of satellite has magnitude `a_2` . Then the ratio `(a_(1))/(a_(2))` is (Assume there is no external force other than the gravitational force of earth before and after the firing of rocket from the satellite)

Explanation

`a_(1)=(F)/(m)=(GM)/(r^(2))`
it is same in both cases
`therefore(a_(1))/(a_(2))=(GM)/(r^(2))`
it is same in both cases
`therefore(a_(1))/(a_(2))=1`