In each situation of column-I, some charge distributions are given with all details explained. In column -II The electrostatic potential energy and its nature is given situation in column -II. Match the proper entries from column-2 to column-1 using the codes given below the columns, Column-I

Options

A. `{:(P,Q,R,S),(1,2,4,3):}`
B. `{:(P,Q,R,S),(4,1,2,3):}`
C. `{:(P,Q,R,S),(1,2,3,4):}`
D. `{:(P,Q,R,S),(2,4,3,1):}`

Explanation

(A). Electrostatic potential energy `=(1)/(4piin_(0))((-Q)^(2))/(2a)=(Q^(2))/(8piin_(0)a)`
(B). Electrostatic potential energy `=(1)/(4piin_(0))[((-Q)xx(-Q))/(5a//2)+((-Q)^(2))/(2(5a//2))]=(3)/(20)(Q^(2))/(piin_(0)a)`
(C). Electrostatic potential energy `=(1)/(4piin_(0))(3Q^(2))/(5a)=(3)/(20)(Q^(2))/(piin_(0)a)`
(D). Electrostatic potential energy `=(1)/(4piin_(0))[(3Q^(2))/(5a)+((-Q)^(2))/(2(2a))+((-Q)^(2))/(2(2a))+((-Q)xx(-Q))/(2a)]=(27Q^(2))/(80piin_(0)a)`