A smooth wedge of mass M is pulled towards left with an acceleration `a= g cot theta` on a horizontal surface and a block of mass m is released w.r.t. wedge. Then answer the following

Time taken by the block to reach the ground is

Options

A. `sqrt((2l sin theta)/g)`
B. `sqrt((2l)/(g sin theta))`
C. `sqrt((2l)/(g cos theta))`
D. `v/(g sin theta)`

Answer

A

Explanation

`N+F_(s) sintheta=mg costheta`
`rArrN=O`
so w.r.t ground block will fall freely.
`h=(1)/(2)g t^(2)` and `h=lsintheta`