A smooth wedge of mass M is pulled towards left with an acceleration `a= g cot theta` on a horizontal surface and a block of mass m is released w.r.t. wedge. Then answer the following

Normal reaction offered by ground to the wedge is

Options

A. `Mg`
B. `(M+m) g cot theta`
C. `mg sin^(2) theta+Mg`
D. `(M+m)g`

Answer

A

Explanation

`N+F_(s) sintheta=mg costheta`
`rArrN=O`
so w.r.t ground block will fall freely.
`h=(1)/(2)g t^(2)` and `h=lsintheta`