A particle moving with velocity (2hati-3...

A particle moving with velocity `(2hati-3hatj)` m/s collides with a surface at rest in xz–plane as shown in figure and moves with velocity `(2hati+2hatj)` m/s after collision. Then coefficient of restitution is :

`2/3`

`sqrt(8/13)`

`4/5`

Text Solution

Verified by Experts

`e=(v_(sep))/(v_(opp))=2/3`

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