A particle is attached to an end of a rigid rod. The other end of the rod is hunged and the rod rotates always remaining horizontal. Its angular speed is increasing at contant rate. The mass of the particle is `m` . The force exerted by the rod on the particle is `vecF` , then:

Options

A. `F ge mg`
B. F is constant
C. The angle between `vec(F)` and horizontal plane decreases
D. The angle between `vec(F)` and the rod decreases

Explanation

`F=sqrt(f^(2)+(mg)^(2))`
Now when the angular speed of the rod is increasing at const. rate the resultant force will be more inclined towards `vec(f)`.

Hence the angle between `vec(F)` and horizontal plane decreases so as with the rod.