A hemispherical bowl of uniform mass distribution of mass ‘M’ is at rest on frictionless horizontal ground sur- face. There is a small insect of mass 'm' on bowl at point ‘A’ of the bowl at rest. Now the insect moves with constant speed ‘v’ relative to bowl in vertical plane. Assume that insect does not slip on the bowl.

When the insect reaches point ‘P’ of the hemisphere the displacement of hemisphere w.r.t. ground is :

Options

A. Zero
B. `(MR)/((M+m))(1-cos theta)` horizontally towards left
C. `(mR)/((M+m))(1-cos theta)` horizontally towards left
D. `(mR(1+cos theta))/((M+m)) (1+cos theta)`

Explanation

`MX=m(R-Rcos theta-X)rArr X=(mR(1- cos theta))/((M+m))`