The instantaneous potential differece between points A and B is :

Options

A. `8sin (50 omegat+37 (pi)/180)`
B. `8 sin(50 pi t-37 (pi)/180)`
C. `10 sin (50 pi t)`
D. `10 cos (50 pit)`

Explanation

Impedence `z=sqrt((8-2)^(2)+(8)^(2))=10 Omega`
Current lags voltage by `37^(@)`, then
`i=10/10 sin (50 pi t-37^(@))`
`V_(AB)=ixxR=8 sin (50 pi t-37^(@))`