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In a series LR circuit, the voltage drop...

In a series LR circuit, the voltage drop across inductor is 8 volt and across resistor is 6 volt. Then voltage applied and power factor of circuit respectively are:

A

14V,0.8

B

10V,0.8

C

10 V,0.6

D

14 V,0.6

Text Solution

Verified by Experts

`V_(L)=8 V,V_(R)=6V,V=sqrt((V_(L)^(2)+V_(R)^(2))=10 V`
Power factor `=cos phi=(V_(R))/V=6/10 =0.6`
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