In a Young's double slit experiment, the separation between the slits is d, distance between the slit and screen is D(Dgtgtd). In the interference pattern, there is a maxima exactly in front for each slit. Then the possible wavelength used in the experiment are:

Options

A. `(d^(2))/D,(d^(2))/(2D),(d^(2))/(3D)`
B. `(d^(2))/D,(d^(2))/(3D),(d^(2))/(5D)`
C. `(d^(2))/(2D),(d^(2))/(4D),(d^(2))/(6D)`
D. none of these

Explanation

To solve the problem, we need to analyze the conditions for the maxima in a Young's double slit experiment. Here’s a step-by-step solution:

### Step 1: Understanding the Setup
In a Young's double slit experiment, we have two slits separated by a distance \( d \) and a screen placed at a distance \( D \) from the slits. The interference pattern created on the screen consists of alternating bright and dark fringes.

### Step 2: Condition for Maxima
For a point on the screen to be a maximum (bright fringe), the path difference between the light coming from the two slits must be an integer multiple of the wavelength \( \lambda \):
\[
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