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In a YDSE, distance between the slits an...

In a YDSE, distance between the slits and the screen is 1m, separation between the slits is 1mm and the wavelength of the light used is `5000nm`. The distance of `100^(th)` maxima from the central maxima is:

A

0.5 m

B

0.577 m

C

0.495 m

D

does not exist

Text Solution

Verified by Experts

For 100 the maximum
`d sin theta=100 lambda`
`sin theta=(100xx5000xx10^(-9))/(1xx10^(-3))=(5xx10^(-4))/(10^(-3))=0.5 =1/2`
`:. y= D tan theta`
`=1xx tan 30`
`=1/(sqrt(3))=(sqrt(3))/3=1.732/3=0.577`
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