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In the figure shown the key is switched ...

In the figure shown the key is switched on at `t=0`. Let `l_1` and `l_2` be the currents through inductors having self inductances `L_1` and `L_2` at any time t respectively. The magnetic energy stored in the inductors 1 and 2 be `U_1` and `U_2`. Then `U_1/U_2` at any instant of time is:

A

`(L_(1))/(L_(2))`

B

`(L_(2))/(L_(1))`

C

`(I_(1))/(I_(2))`

D

`(I_(2))/(I_(1))`

Text Solution

Verified by Experts

Because both inductors are in parallel
`:. L_(1)I_(1)=L_(2)I_(2)`
`(U_(1))/(U_(2))=(1//2 L_(1)I_(1)I_(1))/(1//2L_(2)I_(2)I_(2))=(I_(1))/(I_(2))=(L_(2))/(L_(1))`
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