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In the circuit shown in fig. X(C ) = 100...

In the circuit shown in fig. `X_(C ) = 100 Omega,(X_L)=200 Omega and R=100 Omega`. The effective current through the source is

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`I_(R)=V/R=200/100=2A`
`I'=V/(X_(L)-X_(C))=200/100 =2A`
`I=sqrt(I_(R)^(2)+I'^(2))=2sqrt(2) Amp`.
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