A small block is kept on a platform executing SHM in the horizontal plane, described by `x=A sin omegat`. The time period of SHM is T and the coefficient of friction between the block and the platform is `mu`. The condition that the block does not slip on the platform at any instant is `mu ge (x pi^(2)A)/(gT^(2))` then write the value of 'x'

Explanation

N=Mg
f=ma
As f must be static friction (No slip condition)
`f le mu NrArr ma le mu mg`
or `ma_0 le mu mg`
`:. mAomega^(2) le mu mg`
`:. Omegalesqrt((mug)/A)`
`omega=(2pi)/Tlesqrt((mug)/A)`
`:. Tge 2pisqrt(A/(mug))rArr mu ge (4pi^(2)A)/(g T^(2))`