A uniform rod of mass M and length L, area of cross section A is placed on a smooth horizontal surface. Forces acting on the rod are shown in the digram

Total elastic potential energy stored in the rod is :

Options

A. `(7F^(2)L)/(6AY)`
B. `(11F^(2)L)/(6AY)`
C. `(5F^(2)L)/(6AY)`
D. `(3F^(2)L)/(2AY)`

Explanation

`U=(19 F^(2)L)/(48AY)+(37F^(2)L)/(48AY)=(7F^(2)L)/(6AY)`