The voltage applied to an X-ray tube is 18 kV. The maximum mass of phton emitted by the X-ray tube will be

Options

A. `2xx10^(-13) kg `
B. `3.2xx10^(-36) kg`
C. `3.2xx10^(-32) kg`
D. `9.1xx10^(-31) kg`

Explanation

Energy of photon is given by `mc^(2)` now the maximum energy of photon is equal to the maximum energy of electorn =e V
hence, `mc^(2) =ev implies m=(eV)/(c^(2))=(1.6xx10^(-19)xx18xx10^(3))/((3xx10^(8))^(2))=3.2xx10^(-32) kg`