The difference between `(n + 2)^(th)` Bohr radius and nth Bohr radius is equal to the `(n – 2)^(th)` Bohr radius. The value of n is ?

Explanation

`r_(n) alpha n^(2)`
`r_(n+2)=K(n+2)^(2) implies r_(n)=kn^(2)`
`r_(n-2)=k(n-2)^(2)`
`(n+2)^(2)-n^(2)=(n-2)^(2)implies n=8`