Let the wavelength at which the the spectral emissive power of a black body (at a temperature T) is maximum, be denoted by `lamda_(max)` as the temperature of the body is increased by 1K, `lamda_(max)` decreases by 1 percent. The temperature T of the black body is

Options

A. 100 K
B. 200 K
C. 400 K
D. 288 K

Explanation

`lamda_(m)T=`const.
`lnlamda_(m)=lnT=C`
`(dlamda_(m))/(lamda_(m))+(dT)/(T)=0" "therefore(dlamda_(m))/(lamda_(m))=(dT)/(T)`
Now `(dlamda_(m))/(lamda_(m))=-1%=-(1)/(100)` (-ve sign indicates decreases)
`dT=1` (given)
`thereforeT=100K`