A scale `(alpha=10^(-3)//.^(@)C)` gives correct reading at `0^(@)C` it is sued at a different temperature where the scale measured length 1.015 m line as 1m. Find the temperature in `.^(@)C`, at which this scale is used while taking the measurement.

Explanation

`L=L_(0)(1=alpha_(S)trianglet)`
`1=1.015-1.015xx10^(-3)xxtriangleT`
`triangleT=(15)/(1.015)=15`.