`"arg"(i(sqrt(3) + i)^(6))/(4(1-isqrt(3))^(2))` का मान है

Options

A. `-(pi)/(6)`
B. `(pi)/(6)`
C. `(3pi)/(12)`
D. `(5pi)/(10)`

Answer

B

Explanation

`z = (e^(ipi//2)(2e^(ipi//6))^(6))/(4*(2 * e^(-ipi//3))^(2)) = 4 * e^(i(pi//2 + pi + 2pi//3))`
`therefore z = 4e^(i13pi//6)`
`because "arg"(z) = (13pi)/(6) = 2pi + (ip)/(6) = (pi)/(6)`