यदि `omega` इकाई का सम्मिश्र घनमूल है, तब
`(a + bomega + comega^(2))/(c + aomega + bomega^(2)) + (a +bomega + comega^(2))/(b+comega + aomega^(2))` का मान है

Options

A. 1
B. 0
C. 2
D. `-1`

Answer

D

Explanation

दिया गया व्यंजक
` = (omega^(2)(a +bomega + comega^(2)))/(comega^(2) + aomega^(3) + bomega^(4)) + (omega(a + bomega + comega^(2)))/((bomega +comega^(2) + aomega^(3)))`
` = omega^(2) + omega = - 1 " " [because 1 + omega + omega^(2) = 0]`