Can we have any `n epsilon N`, where `15^n` ends with the digit zero?

Consider the number 4^n where n is a natural number. Check whether there is any value of n which 4^n ends with the digit zero?

Consider the numbers 4^n , where n is a natural number. Cheek whether there is any value of n for which 4^n ends with the digit zero.

Consider the numbers 4^(n) , where n is a natural number. Check whether there is any value of n for which 4^(n) ends with the digit zero.

Consider the numbers 4^(n) , where n is a natural number. Check whether there is any value of n for which 4^(n) ends with the digit zero.

Use proof by contradition to show that there is no value of n for which 6^n ends with the digit zero.

Consider the numbers ,where n is a natural number.Cheek whether there is any value of n for which ends with the digit zero.

Use proof by contradiction to show that there is no value of n for which 6n ends with the digit zero.

Prove that there is no natural number for which 4^n ends with the digit zero.

Prove that there is no natural number for which 4^(n) ends with the digit zero.

Can the number 6^n , n being a natural number, end with the digit 5? Give reason.