The acceleration of a particle in `SHM` is `0.8ms^(-2)`, when its displacement is `0.2m`. The frequency of its oscillation is

The acceleration of a particle executing S.H.M, when it is at its mean position is

For a simple harmonic oscillator, the aceeleration is 3 m//s^(2) when the displacement is 0.03 m. The angular frequency of the oscillator is

The acceleration of a simple harmonic oscillator is 1 m//s^(2) when its displacement from mean position is 0.5 m. Then its frequency of oscillation is

The acceleration of a particle performing a S.H.M. is 0.12 m//s^(2) , when the particle is at a dis"tan"ce of 3 cm from its equilibrium position. What is the period of S.H.M. ?

The acceleration of a particle executing SHM is 0.10 ms^(-2) at a distance of 8xx10^(-2)m from the mean position. Calculate its time period.

Acceleration displacement (a-x) graph of a particle executing S.H.M. is shown in the figure. The frequency of oscillation is (tan theta =8)

Acceleration displacement graph of a particle executing S.H.M is as shown in given figure. The time period of its oscillation is in sec)