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The point(s) on the parabola y^2 = 4x wh...

The point(s) on the parabola `y^2 = 4x` which are closest to the circle`x^2 + y^2 - 24y + 128 = 0` is/are

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equation of circle
`x^2+y^2-24y+128=0`
its center=(0,12)
equation of parabola
`y^2=4x`
where a=1
point P`(at^2,2at)=(t^2,2t)`
normal at point (t)
...
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