`x^2-x-6`if `alpha` and `beta` are the zeroes of `P(x)` then find:

For the given polynomial p(x) = x^(2) - 5x - 1 , if alpha and beta are its zeroes, then find the value of alpha^(2) beta + alpha beta^(2)

For the given polynomial p (x) = x ^(2) - 5x -1, if alpha and beta are its zeroes then find the value of alpha ^(2) beta + alpha beta ^(2)

If alpha , beta are the zeroes of x^2+7x+10 , then alpha beta =

If alpha and beta are zeros of p(x) = x^2 + x - 1 , then find alpha^(2)beta + alphabeta^(2) .

If alpha and beta are zeroes of x^(2)-5x+6 , then find the value of alpha^(2)+beta^(2) .

If alpha and beta are zeroes of x^(2)-5x+6 , then find the value of alpha^(2)+beta^(2) .

If alpha and beta are zeroes of 8x^(2)-6x+1 , then find the value of (1)/(alpha)+(1)/(beta) .

If alpha and beta are zeroes of 8x^(2)-6x+1 , then find the value of (1)/(alpha)+(1)/(beta) .

If alpha and beta are zeroes of x^(2)-7x+5, then find the value (alpha)/(beta)+(beta)/(alpha)=

If alpha and beta are the zeroes of the polynomial x^(2)+6x+9 then form a polynomial whose zeroes are -alpha and -beta