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Show that the function f: N->N , given b...

Show that the function `f: N->N` , given by `f(x)=2x` , is one-one but not onto.

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Here, `f(x) = 2x`
A function is a one-one function such that `f(x_1) = f(x_2)` only if `x_1 = x_2`.
Here, `f(x_1) = 2x_1`
`f(x_2) = 2x_2`
If `f(x_1) = f(x_2)`, then,
`2x_1 = 2x_2 => x_1 = x_2`
`So, f(x)` is one-one function.
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