If `(n!)/(2!(n-2)!) and (n!)/(4!(n-4)!)` are in the ratio 1:2, then `n=`

IF(n!)/((n-2)!) and (n!)/((n-4)!) are in the ratio 1:12, then n=

If (n !)/(2!(n-2)!) and (n !)/(4!(n-4)!) are in the ratio 2:1 , find the value of ndot

If (n!)/(2!(n-2!)) and (n!)/(4!(n-4!)) are in the ratio 2:1, find the value of n.

If (n!)/( 2!( n-2) !) and (eta !)/( 4!(n-4)!) are in the ratio 2: 1 , find the value of n.

I f(n !)/(2!(n-2)!)and(n !)/(4!(n-4)!)a r e i n t h e r a t i o2:1, n!4!(n-4 are in the ratio 2:1, then nn!a) If 21(n -2)1 and

If (n!)/(2!(n-2)!):(n!)/(4!(n-4)!) =2:1 . Find the value of n.

If (n!)/((2!)xx(n-2)!): (n!)/((4!)xx(n-4)!)=2:1 , find the value of n.

(1)/(n!)+(1)/(2!(n-2)!)+(1)/(4!(n-4)!) +….to n terms is equal to