The focal length of a thin lens in vacuum is `f`. If the material of the lens has `mu = 3//2`, its focal length when immersed in water of refractive index `4//3` will be.

Focal length of a lens in air is f. Refractive index of the lens is mu . Focal length changes to f_(1) if lens is immersed in a liquid of refractive index (mu)/(2) and it becomes f_(2) if the lens is immersed in a liquid of refractive index 2 mu . Then

Focal length of a lens in air is f. Refractive index of the lens is mu . Focal length changes to f_(1) if lens is immersed in a liquid of refractive index (mu)/(2) and it becomes f_(2) if the lens is immersed in a liquid of refractive index 2 mu . Then

A convex lens of refractive index 1.5 has a focal length of 20cm in air. Calculate the change is its focal length when immersed in water of refractive index 4/3.

A convex lens of focal length 0.5m in air has a refractive index of 1.5.What will be its focal length when immersed in water of refractive index 1.33 ?

A convex lens of refractive index 1.5 has a focal length of 20 cm in air. Calculate the change in its focal length when it is immersed in water of refractive index 4/3.

A convex lens of refractive index 1.5 has a focal length of 20 cm in air. Calculate the change in its focal length when it is immersed in water of refractive index 4/3.

A convex lens of refractive index 1.5 has a focal length of 18 cm in air. Calculate the change in its focal length when it is immersed in water of refractive index (4)/(3) .