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The sides of a triangle are in the ratio...

The sides of a triangle are in the ratio `1: sqrt3:2.` Then the angles are in the ratio

A

`1 : 3 : 5`

B

`2: 3 : 4`

C

`3 : 2: 1`

D

`1 : 2: 3`

Text Solution

Verified by Experts

Sides are in the ratio `1 : sqrt3 : 2`
Let `a = k, b = sqrt3 k, and c = 2k`
`cosA = (b^(2) + c^(2) - a^(2))/(2bc) = (sqrt3)/(2) rArr A = (pi)/(6)`
`cos B = (c^(2) + a^(2) -b^(2))/(2ac) = (1)/(2) rArr B = (pi)/(3)`
`rArr C = pi - bar(A + B) = (pi)/(2)`
`rArr A: B: C = 1 : 2: 3`
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Knowledge Check

  • The sides of a triangle are in the ratio 1:sqrt3:2 then the angles of the triangle are in the ratio

    A
    A)`1:3:5`
    B
    B)`2:3:4`
    C
    C)`3:2:1`
    D
    D)`1:2:3`
  • The sides of a triangle are in the ratio 1 : sqrt(3) : 2 , then angles of the triangle are in the ratio

    A
    `1 : 3 :5`
    B
    `2 : 3 : 4`
    C
    `3 : 2: 1`
    D
    `1 : 2 : 3`
  • The sides of a triangle are in the ratio 2:sqrt6:sqrt3+1 , then its angles are

    A
    `45^@,45^@,90^@`
    B
    `60^@,30^@,90^@`
    C
    `45^@,60^@,75^@`
    D
    none
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