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Consider a quadratic equaiton az^(2) + ...

Consider a quadratic equaiton `az^(2) + bz + c=0`, where a,b,c are complex number.
The condition that the equaiton has one purely real roots is

A

`(abarb+barab)(b barc-barbc)=(c bara+barca)^(2)`

B

`(abarb-barab)(b barc+barbc)=(cbara+barca)^(2)`

C

`(abarb-barab)(barbc-barbc)=(cbara-barca)^(2)`

D

`(abarb-barab)(b barc-barbc)=(cbara+barca)^(2)`

Text Solution

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The correct Answer is:
c
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