If `a_(1)=1` and `a_(n+1)=(4+3a_(n))/(3+2a_(n)),nge1`, show that `a_(n+2)gea_(n+1)` and if a lim l as `n to oo` the evaluate `lim_(ntooo)a_(n)``

If a_(1)=1 and a_(n+1)=(4+3a_(0))/(3+2a_(n)),n>=1, and if lim_(n rarr oo)a_(n)=a then find the value of a.

If x_(1)=3 and x_(n+1)=sqrt(2+x_(n))" ",nge1, then lim_(ntooo) x_(n) is

If quad 1,a_(1)=3 and a_(n)^(2)-a_(n-1)*a_(n+1)=(-1)^(n) Find a_(3).

If a_(1)=2 and a_(n)-a_(n-1)=2n(n>=2), find the value of a_(1)+a_(2)+a_(3)+....+a_(20)

B={a_(n):n in N,a_(n)+1=2a_(n) and a_(1)=3}

If a_(1)=a, a_(2)=b, a_(n+2)=(a_(n+1)+a_(n))/2, nge 0 then lim_(n to oo) a_(n) is (a+lamda_(1)b)/(lamda_(2)), (lamda_(1),lamda_(2) epsilonI) where lamda_(1)+lamda_(2) is _______

If a_(1)=1, a_(2)=5 and a_(n+2)=5a^(n+1)-6a_(n), n ge 1 . Show by using mathematical induction that a_(n)=3^(n)-2^(n)