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Let A={1,2,3,4,5} and B={-2,-1,0,1,2,3,4...

Let A={1,2,3,4,5} and B={-2,-1,0,1,2,3,4,5}.
Increasing function from A to B is

A

120

B

72

C

60

D

56

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The correct Answer is:
To find the number of increasing functions from set A to set B, we can follow these steps: ### Step 1: Identify the sets Let \( A = \{1, 2, 3, 4, 5\} \) and \( B = \{-2, -1, 0, 1, 2, 3, 4, 5\} \). ### Step 2: Determine the number of elements in each set Count the elements in each set: - The number of elements in set \( A \) is \( |A| = 5 \). - The number of elements in set \( B \) is \( |B| = 8 \). ### Step 3: Choose elements from set B Since we need to create an increasing function from \( A \) to \( B \), we must choose 5 distinct elements from set \( B \). The order of selection does not matter because the function must be increasing. ### Step 4: Calculate the combinations We need to calculate the number of ways to choose 5 elements from 8 elements in set \( B \). This is given by the combination formula: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] where \( n \) is the total number of elements to choose from, and \( r \) is the number of elements to choose. In our case, \( n = 8 \) and \( r = 5 \): \[ \binom{8}{5} = \frac{8!}{5!(8-5)!} = \frac{8!}{5! \cdot 3!} \] ### Step 5: Simplify the combination Calculating \( \binom{8}{5} \): \[ \binom{8}{5} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = \frac{336}{6} = 56 \] ### Final Answer Thus, the number of increasing functions from set \( A \) to set \( B \) is \( 56 \). ---
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ARIHANT MATHS-FUNCTIONS-Exercise (Questions Asked In Previous 13 Years Exam)
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