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Let g(x)=1+x-[x] and f(x)={{:(-1",", x l...

Let `g(x)=1+x-[x]` and `f(x)={{:(-1",", x lt 0),(0",",x=0),(1",", x gt 0):}`, then for all `x`, `f[g(x)]` is equal to

A

`x`

B

`1`

C

`f(x)`

D

`g(x)`

Text Solution

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The correct Answer is:
B
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