Home
Class 12
MATHS
Equation 1/(x+1)^3-3x+sinx=0 has...

Equation `1/(x+1)^3-3x+sinx=0` has

A

no real solution

B

two real and distinct roots

C

exactly one negative root

D

exactly one root between `-1` and 1

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
Promotional Banner

Topper's Solved these Questions

  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS|Exercise Exercise (Statement I And Ii Type Questions)|7 Videos

  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS|Exercise Exercise (Passage Based Questions)|8 Videos

  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS|Exercise Exercise (Single Option Correct Type Questions)|34 Videos

  • DIFFERENTIATION

    ARIHANT MATHS|Exercise Exercise For Session 10|4 Videos

  • ELLIPSE

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|27 Videos

Similar Questions

Explore conceptually related problems

Equation (1)/((x+1)^(3))-3x+sin x=0 has

The equation x^(3) - 3x + 1 = 0 has

If the equation x^(3) - 3x + a = 0 has distinct roots between 0 and 1, then the value of a is

Between any two real roots of the equation e^(x)sinx-1=0 the equation e^(x)cosx+1=0 has

Let- 1<=p<1 show that the equation 4x^(3)-3x-p=0 has a unique root in the interval [(1)/(2),1]

If the equation x^(3)-3x+1=0 has three roos x_(1),x_(2),x_(3) where x_(1)ltx_(2)ltx_(3) then the value of ({x_(1)}+{x_(2)}+{x_(3)}) is ({.} F.P. of x ).

Consider the cubic equation f(x)=x^(3)-nx+1=0 where n ge3, n in N then f(x)=0 has