Home
Class 12
MATHS
To find the point of contact P (x1, y1) ...

To find the point of contact `P (x_1, y_1)` of a tangent to the graph of `y = f(x)` passing through origin O, we equate the slope of tangent to `y = f(x)` at P to the slope of OP. Hence we solve the equation `f' (x) = f(x_1)/x_1` to get `x_1` and `y_1`.Now answer the following questions (7 -9): The equation `|lnmx|= px` where m is a positive constant has a single root for

A

`plt(m)/(e)`

B

`0lt plt(m)/(e)`

C

`0lt p lt(e)/(m)`

D

`plt(e)/(m)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS|Exercise Exercise (Matching Type Questions)|1 Videos
  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS|Exercise Exercise (Single Integer Answer Type Questions)|9 Videos
  • DY / DX AS A RATE MEASURER AND TANGENTS, NORMALS

    ARIHANT MATHS|Exercise Exercise (Statement I And Ii Type Questions)|7 Videos
  • DIFFERENTIATION

    ARIHANT MATHS|Exercise Exercise For Session 10|4 Videos
  • ELLIPSE

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|27 Videos

Similar Questions

Explore conceptually related problems

Find the equation of a curve passing through (1,1) and whose slope of tangent at a point (x, y) is -(x)/(y) .

Determine the equation of the curve passing through the origin,the slope of the tangent of which at any point (x,y) is (x+1)/(y+1)

A curve y=f(x) is passing through (0,0). If slope of the curve at any point (x,y) is equal to (x+xy), then the number of solution of the equation f(x)=1, is :

The graph of the function y=f(x) is shown. Find the number of solutions to the equation ||f(x)|-1|=(1)/(2) .

Find the equation of the cure which passes through the origin and has the slope x+3y-1 at the point (x,y) on it.

The length of tangent at a point P(x_(1),y_(1)) to the curve y=f(x) ,having slope m at P is

If f'(x)=x-1, the equation of a curve y=f(x) passing through the point (1,0) is given by

" Equation of the tangent to "y^(2)=4a(x+a)" having slope "1" is "