Enthalpy of polymerisation of ehtylene, as represented by the reaction , `nCH_(2)=CH_(2)rarr(-CH_(2)-CH_(2)-)` is `-100 kJ` per mole of ehtylene. Given bond enthalpy of C=C bond is `600 kJ mol^(-1)`, enthalpy of C-C bond ( in kJ mol) will be:

Enthalpy of polymerisation of ethylene, as represented by the reaction , Q : N_(2)(g)+2O_(2)(g)toN_(2)O_(4)(g),DeltaH_(Q)=2.31kcal is -100 kJ per mole of ethylene. Given bond enthalpy of C=C bond is 600 kJ mol^(-1) , enthalpy of C-C bond (in kJ mol) will be :

What is the bond enthalpy of C-H bond of CH_(4) ?

The polymerisation of ethylene to linear polyethylene is represented by the reaction nCH_(2)=CH_(2)rarr(-CH_(2)-CH_(2)-)_(n) When n has a large integral value. Given theat the average enthalpies of bond dissociation for C=C and C-C at 298K are +590 and +331kJ mol^(-1) respectively, calculate the enthalpy of polymerisation per mole of ethylene at 298K .

The polymerisation of ethylene to linear polyethylene is represented by the reaction nCH_(2)=CH_(2)rarr(-CH_(2)-CH_(2)-)_(n) When n has a large integral value. Given theat the average enthalpies of bond dissociation for C=C and C-C at 298K are +590 and +331kJ mol^(-1) respectively, calculate the enthalpy of polymerisation per mole of ethylene at 298K .

The enthaply of atomisation for the reaction : CH_(4)(g) to C(g) + 4 H(g) is 1665 kJ "mol"^(-1) .What is the bond enthalpy of C-H bond?

The enthalpy of atomisation for the reaction CH_(4) (g) rarr C (g) + 4H (g) " is " 1665 kJ mol^(-1) . What is the bond energy of C - H bond ?