`8` litre of `H_(2)` and `6` litre of `Cl_(2)` are allowed to react to maximum possible extent. Find out the final volume of reaction mixture. Suppose `P` and `T` remains constant throughout the course of reaction.

Explanation

`{:(,H_(2)+,Cl_(2),rarr,2HCl),("Volume before reaction",8"litre",6"litre",,),("Volume after reaction",2,0,,12"litre"):}`
`:.` Volume after reaction`=` volume of `H_(2)` left `+` volume of `HCl` formed `= 2+12 = 14` litre